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Asked by sky

log 5 ã5

log7 (1/49)
14 years ago

Answers

Answered by Max
Here are some examples to help you.

log2 32 = ?
2^? = 32
? = 5

log3 1/9 = ?
3^? = 1/9
? = -2

As you can see, if y = logb x, then b^y = x.
14 years ago

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help in solving log7 (1/49) = x y = log7(x^2 - 6x - 2) this is base seven is the answer 2x-6/(x^2-6x-2) Log7x=log7 4+log7 3 please help I can not anderstand thanks simplify log7 7^x Evaluate log7 49^2 + log7 7 log7*7^x Given the function f(x)=log7 x , which of the following functions is the transformation of f(x)... log7 (0) log7 90 in form log m/log n
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