Asked by Lisa

help in solving log7 (1/49) = x
Answered by bobpursley
isn't 7^-2 = 1/49?

if so, log7 (1/49)=-2
Answered by Reiny
log7 (1/49) = x is equivalent to

7^x = 1/49 by the definition of logarithms, thus ...
7^x = 49^-1
7^x = (7^2)^-1
x = -2
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