Asked by Lisa
                help in solving log7 (1/49) = x
            
            
        Answers
                    Answered by
            bobpursley
            
    isn't 7^-2 = 1/49?
if so, log7 (1/49)=-2
    
if so, log7 (1/49)=-2
                    Answered by
            Reiny
            
    log7 (1/49) = x is equivalent to
7^x = 1/49 by the definition of logarithms, thus ...
7^x = 49^-1
7^x = (7^2)^-1
x = -2
    
7^x = 1/49 by the definition of logarithms, thus ...
7^x = 49^-1
7^x = (7^2)^-1
x = -2
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