a = change in speed / time
average speed = (75/2 )meters/ second
so time = distance/speed = .75meters/(75/2 meters/second) =2*10^-4 seconds
acceleration = 75/2*10^-4 = 372500 m/s^2
An arrow is accelerated for a displacement of 75cm [fwd] while it is on the bow. If the arrow leaves the bow at a velocity of 75m/s [fwd], what is the average acceleration while on the bow?
2 answers
Displacement = 75cm = 0.75m
Initial velocity = 0
Velocity 2 = 75 m/s [fwd]
Acceleration while on the bow = ?
Use the following equation to solve for time.
d = ( (v2 + v1)/2 ) x t
t = d(2/(v2+v1))
t = 0.75(2/(75+0))
t = 0.02s
Plug all the values we have in the following kinematics equation for acceleration.
v2 = v1 + at
a = (v2 - v1)/t
a = (75 - 0)/0.02
a = 3750 m/s^2
Therefore, the acceleration is 3.8 x 10^3 m/s^2 [fwd]
Initial velocity = 0
Velocity 2 = 75 m/s [fwd]
Acceleration while on the bow = ?
Use the following equation to solve for time.
d = ( (v2 + v1)/2 ) x t
t = d(2/(v2+v1))
t = 0.75(2/(75+0))
t = 0.02s
Plug all the values we have in the following kinematics equation for acceleration.
v2 = v1 + at
a = (v2 - v1)/t
a = (75 - 0)/0.02
a = 3750 m/s^2
Therefore, the acceleration is 3.8 x 10^3 m/s^2 [fwd]
0 answers