Ask a New Question

Question

An electron is accelerated by a constant electric field of magnitude 325 N/C.
(a) Find the acceleration of the electron. (m/s^2)
(b) Use the equations of motion with constant acceleration to find the electron's speed after 1.05 10-8 s, assuming it starts from rest. (m/s)
13 years ago

Answers

Elena
m•a=e•E,
a = e•E/m = 1.6•10^-19•325/9.1•10^-31 = …
v = a•t = ...
13 years ago

Related Questions

An electron is accelerated by a 4.7 kV potential difference. How strong a magnetic field must be exp... An electron is accelerated by a 6.4 kV potential difference. The charge on an electron is 1.60218 ×... An electron is accelerated in the uniform field E = 2.0 x 104 N/C between two parallel charged plate... An electron is accelerated from rest through a potential difference that has a magnitude of 2.90 × 1... An electron is accelerated from rest by a uniform electric field of 3310V/M that is vertically point... An electron is accelerated by a uniform electric field (1000 V/m) pointing vertically upward. Use en... when an electron is accelerated through a potential difference of 1 V, the kinetic energy at the end... An electron accelerated from rest through a potential difference of 50v acquires a speed of 4.2x10^6... An electron was accelerated from rest across the potential difference between two parallel plates. I...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use