A 0.02 kg-lead bullet traveling 200 m/s strikes an armor plate and comes to a stop. If all of it's energy is converted to heat that it absorbs, what is the temperature change?

Answer 1

(1/2)MV^2 = M C*(delta T)
Mass M cancels out. C is the specific heat of lead.
Solve for the temperature change, delta T

delta T = V^2/(2*C)

The specific heat C must have units of
Joules/(kg*degC). Don't use units based on calories