Asked by Ashleigh

a lead bullet is placed in a pool of mercury. what fractional part of the volume of the bullet is submerged?

Answers

Answered by bobpursley
well, the lead displaces mercury such that the weight of the mercury is equal to the weight of the lead.

weight of mercury displaced= densitymercury*volumeleadsubmerged

weight of lead= densitylead*volumelead

so set them equal

Volumesubmerged/totalvolume= densitylead/densitymercury
Answered by Ashleigh
Perfect!
Since the density of lead is 11.3 x 10^3 kg/m^3 and the density of mercury is 13.6 x 10^3 kg/m^3, the answer is 0.831.
Thanks much!
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