Asked by taylor
A 3.35g lead bullet at 31.0°C is fired at a speed of 255 m/s into a large block of ice at 0°C, in which it embeds itself. What quantity of ice melts?
Answers
Answered by
Damon
Ke = (1/2) m v^2 = .5*.00335 * 255^2
in Joules
= mass * heat of fusion of water
= 3.35 * 333 J/gram
in Joules
= mass * heat of fusion of water
= 3.35 * 333 J/gram
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