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A simple pendulum consists of a light string 1.70 m long with a small 0.490 kg mass attached. The pendulum starts out at 45^\ci...Asked by Luis
A simple pendulum consists of a light string 1.70 m long with a small 0.490 kg mass attached. The pendulum starts out at 45ยบ below the horizontal and is given an initial downward speed of 1.50 m/s.
find:
At the bottom of the arc, determine the centripetal acceleration of the bob.
At the bottom of the arc, determine the tension in the string.
find:
At the bottom of the arc, determine the centripetal acceleration of the bob.
At the bottom of the arc, determine the tension in the string.
Answers
Answered by
bobpursley
the KE at the bottom equals the initial PE (mgh) 0f the bob.
1/2 mv^2=mg(1.70cos45)
solve for v. then V^2/r
tension= mg+mv^2/r
1/2 mv^2=mg(1.70cos45)
solve for v. then V^2/r
tension= mg+mv^2/r