Asked by Kathrine
A simple pendulum consists of a 3 kg point of mass hanging at the end of a 2 m long light string that is connected to a pivot point.
a. Calculate the magnitude of the torque (due to gravitational force) around this pivot point when the string makes a 5 degree angle with the vertical.
b. Repeat this calculation for an angle of 15 degrees.
a. Calculate the magnitude of the torque (due to gravitational force) around this pivot point when the string makes a 5 degree angle with the vertical.
b. Repeat this calculation for an angle of 15 degrees.
Answers
Answered by
drwls
The torque about the pivot point
is
T = M g L sin A
A is the angle, M the mass and L is the string length
is
T = M g L sin A
A is the angle, M the mass and L is the string length
Answered by
Kathrine
Thanks a lot, we didn't get that formula. That might be why I was having problems. :)
Answered by
Anonymous
5.299
Answered by
Dalya
Good
Answered by
Maria
T=Fd sin() 9.8=gravity
T=(3)(9.8)(2)(sin(5))
T=5.1Nm
T=(3)(9.8)(2)(sin(15))
T=15 Nm
T=(3)(9.8)(2)(sin(5))
T=5.1Nm
T=(3)(9.8)(2)(sin(15))
T=15 Nm
Answered by
Emran
Nice
Answered by
s
Why isn't it negative? Gravity would be negative in this situation if I'm not mistaken.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.