Asked by ryan
A simple pendulum consists of a ball of mass
5.39 kg hanging from a uniform string of mass
0.0789 g and length L. The period of oscilla-
tion for the pendulum is 2.51 s.
Determine the speed of a transverse wave
in the string when the pendulum is station-
ary and hangs vertically. The acceleration of gravity is 9.8 m/s2 .
Answer in units of m/s.
5.39 kg hanging from a uniform string of mass
0.0789 g and length L. The period of oscilla-
tion for the pendulum is 2.51 s.
Determine the speed of a transverse wave
in the string when the pendulum is station-
ary and hangs vertically. The acceleration of gravity is 9.8 m/s2 .
Answer in units of m/s.
Answers
Answered by
bobpursley
Ignore the mass of the string in determining the period of the pendulum.
Tension=5.39g
massperunitlengthstring=.0789/L
periodpendulum=2PI sqrt (L/g)
solve for L, given pendulum.
wavespeed= (from the law of string)
wavespeed= sqrt (Tension/(mass/length))
Tension=5.39g
massperunitlengthstring=.0789/L
periodpendulum=2PI sqrt (L/g)
solve for L, given pendulum.
wavespeed= (from the law of string)
wavespeed= sqrt (Tension/(mass/length))
Answered by
ronda
Im still having difficulty coming up with the correct answer.
Answered by
bobpursley
post your work, please, I will check it. Ahhh. did you work mass in kg?
Answered by
ronda
i have sample homework with solution and different numbers. Mass=5.51kg Ms=0.0754g T=1.39s.
g(1.39)^2/4*pi^2=.4796
sqrt(5.51/(.000754/.4796))=59.2
answer on this problem is 586.072 m/s
g(1.39)^2/4*pi^2=.4796
sqrt(5.51/(.000754/.4796))=59.2
answer on this problem is 586.072 m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.