Asked by laura

a simple pendulum consists of a bob of mass 1.8 kg attached to a string of length 2.3 m. the pendulum is held at an angle of 30 from the vertical by a light horizontal string attached to a wall, as shown above. calculate the tension in the horizontal string. when the horizontal string is cut, calculate the speed of the bob.

Answers

Answered by El brujo Pirujo
pos orale... contestenla que trueno la clase :(
Answered by 屁嗅探器
Incredible that in all these years nobody has answered you. I also had this problem and I got Tv*cos(30)=mg which solved out to 20.4N for the vertical tension and then to find the horizontal tension I did this, 20.4*sin(30)=10.4N, and so 10.4N is our horizontal tension.

As for the velocity I first solved for the height difference so (y=2.3-2.3cos(30)), then Potential energy with Pe=mgh (Pe=1.8*9.8*0.3). From there I plugged the potential energy in with kinetic energy to solve for the velocity (because Pe=Ke) so that equation would be (Ke=.5MV^2), then with the values plugged in (6=.9kg*V^2). This should solve out to 2.6 m/s.

Finally, for the period of the pendulum, our equation will look like (T=2Pi*root(L/g)) (in this case T=period, and L is of course length). Plugging in our values this equation will be something like (T=6.3*4.7) depending on how you round out which should give you a period of 2.9 seconds although again rounding will affect this a slight bit.

Anyway, I hope you can appreciate this answer 8 years late, and as for anyone else reading in the future, I hope this helps!
Answered by sup
its weird, bc this guy is probably like at least 27 years old LULW Weirdchamp

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