The actual efficiency is
Wout/Qin = 160/450 = 35.56%
If this is 57% of the carnot efficiency, that latter is 35.56%/.57 = 62.4%
Since the Carnot efficiency is
1 - Tlow/Thigh = 0.624
Tlow/Thigh = 0.376
Wout/Qin = 160/450 = 35.56%
If this is 57% of the carnot efficiency, that latter is 35.56%/.57 = 62.4%
Since the Carnot efficiency is
1 - Tlow/Thigh = 0.624
Tlow/Thigh = 0.376
Efficiency = (1 - Tc/Th)
Given that the efficiency of the given engine is 57% of the efficiency of a Carnot engine, we can write:
Efficiency of given engine = 0.57 x Efficiency of Carnot engine
Plugging in the values, we have:
0.57 = (0.57 x (1 - Tc/Th))
Simplifying, we get:
1 - Tc/Th = 0.57/0.57
1 - Tc/Th = 1
Now, we can solve for the ratio Tc/Th:
Tc/Th = 1 - 1
Tc/Th = 0
This implies that the temperature of the low-temperature reservoir (Tc) is 0 Kelvin, which is not physically possible. Therefore, there appears to be an error or inconsistency in the given information or the calculations. Please double-check the values or provide additional information to proceed with the correct calculation.