Asked by Stefan
In one cycle a heat engine absorbs 530 J from a high-temperature reservoir and expels 310 J to a low-temperature reservoir. If the efficiency of this engine is 55% of the efficiency of a Carnot engine, what is the ratio of the low temperature to the high temperature in the Carnot engine?
Answers
Answered by
drwls
The work out of the heat engine is 530-310 = 220 J per cycle and its efficiency is 220/530 = 41.5%
If the Carnot engine is 1/0.55 times higher than 41.5%, that would be 75.5%
The Tlow/Thi ratio of a Carnot engine with 74.5% effiency would have to be
1 - Tlow/Thi = 0.745
Tlow/Thi = 0.255
If the Carnot engine is 1/0.55 times higher than 41.5%, that would be 75.5%
The Tlow/Thi ratio of a Carnot engine with 74.5% effiency would have to be
1 - Tlow/Thi = 0.745
Tlow/Thi = 0.255
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