Asked by Lance
Propane, C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would need to provide 383 kJ of heat.
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)
ΔH = −2043 kJ
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)
ΔH = −2043 kJ
Answers
Answered by
drwls
That is 2043 kJ of heat release per mole of fuel. Each mole of propane has a mass of 3*12 + 8*1 = 44 grams.
You need (383/2043)*44 g of propane
You need (383/2043)*44 g of propane