Asked by Jessica
A sample of propane(c3h8)has 3.84x10^24 H atoms.
a) how many carbon atoms does the sample contain?
b) what is the total mass of the sample?
a) how many carbon atoms does the sample contain?
b) what is the total mass of the sample?
Answers
Answered by
Dr Russ
From the formula (C3H8) [please use capital letters for element symbols] we see that there are 3 C atoms for 8 H atoms. If we had 16 H atoms there would be 6 C atoms for example.
Thus is there are 3.84x10^24 H atoms.
a) then there are (3/8)x3.84x10^24 C atoms
b) there are a couple of ways to do this.
If the sample contains 3.84x10^24 H atoms and each molecule contains 8 H atoms then there are 3.84x10^24/8 molecules of propane. Each mole contains 6 x 10^23 molecules so there are
3.84x10^24/(8 x 6 x 10^23 )moles
the molar mass of propane is
(3x12)+(8x1) g mole^-1
hence find the mass as
mass= molar mass x number of moles
Thus is there are 3.84x10^24 H atoms.
a) then there are (3/8)x3.84x10^24 C atoms
b) there are a couple of ways to do this.
If the sample contains 3.84x10^24 H atoms and each molecule contains 8 H atoms then there are 3.84x10^24/8 molecules of propane. Each mole contains 6 x 10^23 molecules so there are
3.84x10^24/(8 x 6 x 10^23 )moles
the molar mass of propane is
(3x12)+(8x1) g mole^-1
hence find the mass as
mass= molar mass x number of moles
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