Asked by ashley --- HELP PLEASEE!!!
A wire of length L m has 2 ohms resistance. It is stretched twice its original length and its area becomes half of its original area. What is its new resistance?
Answers
Answered by
MathMate
A wire's resistance is proportional to its length and inversely proportional to its area.
So if the original resistance was R=2Ω, the new resistance is then:
R1=2Ω * (2L/L)* (A/(A/2))
= 2Ω * (2)*(2)
= 8Ω
So if the original resistance was R=2Ω, the new resistance is then:
R1=2Ω * (2L/L)* (A/(A/2))
= 2Ω * (2)*(2)
= 8Ω
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.