Question
A wire of length 380 cm is cut into 10 pieces.Each piece is then bent to form a square.The dimensions of the first three smallest squares are shown below.Find the value of x and hence,the area of the eighth largest square.
x cm[ ] (x+1)cm [ ]
x cm (x+1)cm
(x+2)cm[ ]
(x+2)cm
Answer: x=5
Area=144cm
x cm[ ] (x+1)cm [ ]
x cm (x+1)cm
(x+2)cm[ ]
(x+2)cm
Answer: x=5
Area=144cm
Answers
Steve
clearly the lengths of the sides are sequential integers, starting with x.
The sum of the perimeters is thus
4(10x + 9*10/2) = 40x+180 = 380
...
The sum of the perimeters is thus
4(10x + 9*10/2) = 40x+180 = 380
...