Question
a wire whose length is at most 114cm,is bent to form a rectangle.If the length of the rectangle is 5cm longer than the width, what is the maximum area of the rectangle?
Answers
width -- x
length --- x+5 , it said so
So, 2 widths + 2 lengths = 114
form your equation, find the width and length
Area = length x width
length --- x+5 , it said so
So, 2 widths + 2 lengths = 114
form your equation, find the width and length
Area = length x width
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