Asked by Adam
How would you integrate
18x-33/√(3x^2-11x+6)
18x-33/√(3x^2-11x+6)
Answers
Answered by
Reiny
I assume you meant:
(18x-33)/√(3x^2-11x+6)
or
(18x-33)/(3x^2-11x+6)^(-1/2)
did you notice that 18x-33 is 3 times the derivative of 3x^2 - 11x + 6 ?
so by just plain common intuition ....
6(3x^2 - 11x + 6)^(1/2) + c
or
6√(3x^2 - 11x + 6) + c
(check by taking the derivative, it works)
(18x-33)/√(3x^2-11x+6)
or
(18x-33)/(3x^2-11x+6)^(-1/2)
did you notice that 18x-33 is 3 times the derivative of 3x^2 - 11x + 6 ?
so by just plain common intuition ....
6(3x^2 - 11x + 6)^(1/2) + c
or
6√(3x^2 - 11x + 6) + c
(check by taking the derivative, it works)
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