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Asked by Ben

Find the average value of f(t)=-2te^(-t^2) on the interval [0,3]
17 years ago

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Answered by Count Iblis
This is 1/3 times the integral from zero to 3 of f(t) = 1/3 [1-exp(-9)]
17 years ago
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Find the average value of f(t)=-2te^(-t^2) on the interval [0,3]

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