Asked by Robin
A) Find the average value of
f(x)=x^3-x+1 on the interval (0,2)
B) Find c so that f(c)equals the average value
f(x)=x^3-x+1 on the interval (0,2)
B) Find c so that f(c)equals the average value
Answers
Answered by
Steve
avg value is area divided by width, so
1/2 ∫[0,2] x^3-x+1 dx
= 2
So, since the area is 4, and the width is 2, a rectangle of height 2 will have the same area.
We need to solve
f(x) = 2
x^3-x+1 = 2
x^3-x-1 = 0
x = 1.32
1/2 ∫[0,2] x^3-x+1 dx
= 2
So, since the area is 4, and the width is 2, a rectangle of height 2 will have the same area.
We need to solve
f(x) = 2
x^3-x+1 = 2
x^3-x-1 = 0
x = 1.32
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.