Question

A ball rolling down an incline travels 6.0 cm in the first 0.25 econds, and 24 cm in the first 0.50 seconds. Find:

a)The average speed for the first quarter second time interval


B) The average speed for the second time interval


C) Find its acceleration

Answer 1

a) 6/.25 = 24 cm/s = .24 m/s
b) 24/.5 = 48 cm/s = .48 m/s
c) need exact speed at center of intervals, it is half that at the end of the interval since the intervals start with velocity zero and v linear with time
speed at .125 seconds = 24 cm/s = .24 m/s
speed at .25 seconds = 48 = .48 m/s
change in speed /change in time = (48-24)/(.25-.125)
= 24/(1/8) = 24*8 = 192 cm/s^2 = 1.92 m/s^2

Answer 2

A ball rolling down an incline travels 6.0 cm in the first 0.25 seconds, and 24 cm in the first 0.50 seconds. What is the average speed for the first quarter second time interval? average speed for the second quarter second time interval? its acceleration?

Vave =

Vave =

a =