Asked by Vanessa
Find the average value of the function f over the interval [0, 8].
f(x) = 5e^-x
f(x) = 5e^-x
Answers
Answered by
Steve
that would be
(∫[0,8] 5e^-x dx)/(8-0)
= 5/8 (1-e^-8)
(∫[0,8] 5e^-x dx)/(8-0)
= 5/8 (1-e^-8)
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