Asked by xX_Supaman_Xx
Solve d/dx x(ln(x)-1)
I had:
=d/dx xln(x) - d/dx 1
=d/dx ln(x)^x
=x^(-x-1) [and this is wrong]
Can someone show me the correct answer and working please?
I had:
=d/dx xln(x) - d/dx 1
=d/dx ln(x)^x
=x^(-x-1) [and this is wrong]
Can someone show me the correct answer and working please?
Answers
Answered by
Reiny
it looks like you are taking the derivative of
f(x) = x[ln(x) - 1]
using the product rule I get:
f'(x) = x(1/x) + [ln(x)-1](1)
= 1 + ln(x) - 1
= ln(x)
f(x) = x[ln(x) - 1]
using the product rule I get:
f'(x) = x(1/x) + [ln(x)-1](1)
= 1 + ln(x) - 1
= ln(x)
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