Asked by ben
how would you solve these equations?
y^2+2y-2x+5=0
and
(x^2/16)-(y+1)^2/(25)=1
thank you!
y^2+2y-2x+5=0
and
(x^2/16)-(y+1)^2/(25)=1
thank you!
Answers
Answered by
bobpursley
What exactly do you mean by solve? if you have two variables, it takes two independent equations to find possible solutions
Answered by
ben
well for the first one i'm pretty sure it is a parabola, and i'm confused on how you would find the vertex focus and directrix
Answered by
Mgraph
y^2+2y=2x-5
y^2+2y+1=2x-5+1
(y+1)^2=2x-4
(y+1)^2=4*(1/2)(x-2)
vertex (2,-1)
focus (2.5,-1)
directrix x=1.5
y^2+2y+1=2x-5+1
(y+1)^2=2x-4
(y+1)^2=4*(1/2)(x-2)
vertex (2,-1)
focus (2.5,-1)
directrix x=1.5
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