Asked by ben

how would you solve these equations?

y^2+2y-2x+5=0

and

(x^2/16)-(y+1)^2/(25)=1

thank you!
Answered by bobpursley
What exactly do you mean by solve? if you have two variables, it takes two independent equations to find possible solutions
Answered by ben
well for the first one i'm pretty sure it is a parabola, and i'm confused on how you would find the vertex focus and directrix
Answered by Mgraph
y^2+2y=2x-5
y^2+2y+1=2x-5+1
(y+1)^2=2x-4
(y+1)^2=4*(1/2)(x-2)

vertex (2,-1)
focus (2.5,-1)
directrix x=1.5
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