Asked by Marie
Please help me solve this equation.
log[2](3)+log[2](x)=log[2](5)+log[2](x-2)
1. Solve equation by setting up algebraically.
2. Use appropriate properties of Logarithm to reduce the number of logarithmic terms to only one.
3. Solve logarithmic equation.
log[2](3)+log[2](x)=log[2](5)+log[2](x-2)
1. Solve equation by setting up algebraically.
2. Use appropriate properties of Logarithm to reduce the number of logarithmic terms to only one.
3. Solve logarithmic equation.
Answers
Answered by
MathMate
log[2](3)+log[2](x)=log[2](5)+log[2](x-2)
=>
log[2](3*x) = log[2](5*(x-2))
=>
3x=5(x-2)
=>
5x-3x=5*2
=>
2x=10
=>
x=5
Check by putting x into the original equation and see if it balances.
=>
log[2](3*x) = log[2](5*(x-2))
=>
3x=5(x-2)
=>
5x-3x=5*2
=>
2x=10
=>
x=5
Check by putting x into the original equation and see if it balances.
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