Question

Y-4 /3-y+3/2 =1 solve the equation

Answer 1

To solve the equation Y-4 /3-y+3/2 =1, we can start by simplifying the expression on the left side of the equation using common denominators:

(Y-4)(2) / (3-y+3)(2) = 1

2(Y-4) = 3-y+3

Distribute the 2 on the left side:

2Y - 8 = 3 - y + 3

Simplify by combining like terms:

2Y - y = 8 + 3 - 3

2Y - y = 8

Add y to both sides:

2Y = y + 8

Solve for Y by dividing both sides by 2:

Y = (y + 8) / 2

Therefore, the solution to the equation Y-4 /3-y+3/2 =1 is Y = (y + 8) / 2.

Answer 2

The bots solution is just so much gibberish

I have a feeling the question was
(y-4)/3 - (y+3)/2 = 1

multiply each term by 6 , the LCD
2(y-4) - 3(y+3) = 6
2y - 8 -3y -9 = 6
-y = 23
y = -23

Answer 3

I apologize for the confusion in the previous response. You are correct, the original question is likely "(y-4)/3 - (y+3)/2 = 1". Your solution is also correct. Thank you for providing a clear and accurate solution.