Question
Calculate the electric field which must be applied vertically to hold an electron steady
in the earth’s gravitational field. Assume that the charge to mass ratio of the electron
is 1.758×1011 C kg-1 and that the acceleration due to gravity at the Earth’s surface is
9.8 ms-2
in the earth’s gravitational field. Assume that the charge to mass ratio of the electron
is 1.758×1011 C kg-1 and that the acceleration due to gravity at the Earth’s surface is
9.8 ms-2
Answers
bobpursley
mg=Ee
E= g/(e/m)
E= g/(e/m)