Asked by Chris
100,000J of heat is added to a 2.0KG of ice at -8degrees C. How much ice melts?
Answers
Answered by
drwls
The heat of fusion is 80 cal/g = 335 J/g
The specific heat of ice 2.11 J/g*degC
To heat the ice to 0 C requires
2000 g * 8 C *2.11 J/c*C = 33,760 J
There is more than enough heat to melt all of the ice.
The specific heat of ice 2.11 J/g*degC
To heat the ice to 0 C requires
2000 g * 8 C *2.11 J/c*C = 33,760 J
There is more than enough heat to melt all of the ice.
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