Asked by idk

How much heat has to be added to change 0.500 kg ice from -10C completely to a steam of 110C. The specific heat of ice, water and steam is 2090 J/kg ⋅K, 4186 J/kg⋅K, 2010 J/kg ⋅K respectively. Given that the heat J/kg, the heat of J/kg. Draw of fusion for ice is 3.34×10^5 vaporization for water is 2.26×10^6 the heat curve that shows the process as thermal energy is added to the system. Calculate the heat added to each five steps of this process.
Answered by idk
answer please
Answered by idk
helppppp
Answered by R_scott
heat ice

melt ice ... heat of fusion * mass

heat water

boil water ... heat of vaporization * mass

heat steam

for the three heating steps ... mass * specific heat * Δt
Answered by anne
can you plug in the numbers please. its kinda confusing than you
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