1.14 g/mL x 111 mL = 126.5 grams soln
100 mL H2O x 1.00 g/mL = 100 grams
difference is 26.5 grams.
A quantity of sulfuric acid is added to 100. mL of water. The final volume of the solution is 111 mL and has a density of 1.14 g/mL. What mass of acid was added? Assume the density of the water is 1.00 g/mL.
1 answer