Sulfuric acid is diluted in water to make new mixtures. In one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31$ acid solution. The contents of the containers are mixed together? What's the percentage strength of the acid in the mixture?

Answer 1

14 % = 0.14

31 % = 0,31

Total volume of containers:

72 ml + 64 ml = 136 ml

Volume of acid in first container:

72 ml * 0.14 = 10.08 ml

Volume of acid in second container:

64 ml * 0.31 = 19.84 ml

Volume of alcohol in the mixture :

10.08 ml + 19.84 ml = 29.92 ml

Percentage strength of the acid in the mixture:

( 29.92 / 136 ) * 100 % = 0.22 *100 % = 22 %

Answer 2

.14 * 72 = ? mL acid

.31 * 64 = ? mL acid

64 + 72 = ? mL mixture

divide the TOTAL mL of acid by the mixture volume to find the % acid