Question

Im having a hard time figuring out this problem:

Use the function, y=-(x+1)^2 +2, to answer the following parts.

Find the y-intercept
y=-(0+1)^2 +2
y=-(1)^2 +2
y=-1+2
y=1 is my answer

Find the x-intercept
0=-(x+1)^2 +2
0=-((x^2)+(1^2))+2
0=-x^2 - 1 + 2
sq.rt(x^2)= sq.rt(1)
x=1 is my answer but im not sure about it.

I need help with:
Finding the vertex, increasing interval,and decreasing interval.

Answer 1

Is the vertex (-1,2)
Increasing interval (-2,1)
Decreasing interval(1,-2)

Do the x-intercept =1?

Answer 2

1. y= 1 is correct.

2. Y = -(X+1)^2 + 2 = 0,
-(X+1)^2 = -2,
Divide both sides by -1:
(X+1)^2 = 2,
Take sqrt of both sides:
X+1 = sqrt2 = 1.4142,
X = 1.4142 - 1 = 0.4142. = x-Intercept

3. V(-1,2) is correct.