Asked by Shikra

Expand the expression ln 2y/x
How does a person go about expanding that thing?

Answers

Answered by MathMate
Are you working on series and sequences?
For example,

ln(1+x) = x - (x^2)/2 + (x^3)/3 -(x^4)/4... where |x|<1

or

ln(x) = (x-1) - ((x-1)^2)/2 + ((x-1)^3)/3 -.... where 0<x≤2

etc.
Answered by Shikra
I don't think we are working on series and sequences becuase that stuff doesnt look familiar... we are just doing logorithms and ln stuff... is there any other way you can expand it?

thanks!
Shikra
Answered by MathMate
In that case, it would require the laws of logarithms, such as:

log(a)+log(b) = log(ab)
log(a)-log(b) = log(a/b)
b*log(a) = log(a<sup>b</sup>)
log(a)/b = log(a^(1/b))
...
etc.
Expand 2y/x into 2*y÷x
and use the above laws to expand the logarithm part.

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