Asked by Shikra
                Expand the expression ln 2y/x
How does a person go about expanding that thing?
            
        How does a person go about expanding that thing?
Answers
                    Answered by
            MathMate
            
    Are you working on series and sequences?
For example,
ln(1+x) = x - (x^2)/2 + (x^3)/3 -(x^4)/4... where |x|<1
or
ln(x) = (x-1) - ((x-1)^2)/2 + ((x-1)^3)/3 -.... where 0<x≤2
etc.
    
For example,
ln(1+x) = x - (x^2)/2 + (x^3)/3 -(x^4)/4... where |x|<1
or
ln(x) = (x-1) - ((x-1)^2)/2 + ((x-1)^3)/3 -.... where 0<x≤2
etc.
                    Answered by
            Shikra
            
    I don't think we are working on series and sequences becuase that stuff doesnt look familiar... we are just doing logorithms and ln stuff... is there any other way you can expand it?
thanks!
Shikra
    
thanks!
Shikra
                    Answered by
            MathMate
            
    In that case, it would require the laws of logarithms, such as:
log(a)+log(b) = log(ab)
log(a)-log(b) = log(a/b)
b*log(a) = log(a<sup>b</sup>)
log(a)/b = log(a^(1/b))
...
etc.
Expand 2y/x into 2*y÷x
and use the above laws to expand the logarithm part.
    
log(a)+log(b) = log(ab)
log(a)-log(b) = log(a/b)
b*log(a) = log(a<sup>b</sup>)
log(a)/b = log(a^(1/b))
...
etc.
Expand 2y/x into 2*y÷x
and use the above laws to expand the logarithm part.
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