Asked by Hannah
                Find the derivative of the following:
1=x^2+4xy+4y
My answer is 2x. Is this correct?
            
        1=x^2+4xy+4y
My answer is 2x. Is this correct?
Answers
                    Answered by
            Hannah
            
    Also, solve: ln(x^2-5)=0
take e of both sides
x^2-5=1
x^2=6
x=sqrt6 Is this correct?
    
take e of both sides
x^2-5=1
x^2=6
x=sqrt6 Is this correct?
                    Answered by
            Reiny
            
    to find the derivative of 1=x^2+4xy+4y
I have to know if you are finding dy/dx or not
if so, then you have to use implicit differentiation
0 = 2x + 4x(dy/dx) + 4y + 4dy/dx
-2x - 4y = dy/dx(4x + 4)
dy/dx = (-2x-4y)/(4x+4)
= -(x+2y)/(2x+2)
for the last, you should have
x = ± √6
remember , we cannot take ln or log of a negative, but since the x is squared first, both ±√6 will work
    
I have to know if you are finding dy/dx or not
if so, then you have to use implicit differentiation
0 = 2x + 4x(dy/dx) + 4y + 4dy/dx
-2x - 4y = dy/dx(4x + 4)
dy/dx = (-2x-4y)/(4x+4)
= -(x+2y)/(2x+2)
for the last, you should have
x = ± √6
remember , we cannot take ln or log of a negative, but since the x is squared first, both ±√6 will work
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