Asked by Brain box
find the derivative of the following: (a) e^tanx (b) e^sin4x?
Answers
Answered by
oobleck
again, use the chain rule
d/dx e^tanx = e^tanx * sec^2x
d/dx e^sin4x = e^sin4x * cos4x * 4
d/dx e^tanx = e^tanx * sec^2x
d/dx e^sin4x = e^sin4x * cos4x * 4
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