Find the derivative of the following questions;

Question

³√2t/(t^2-4)

Every thing is under the ³√ and the / is a fraction bar.

My answer is y'= t(2t)^3
Can you check my answer please

Answer 1

y= (2t/(t^2-4)^1/3
let u = (t^2-4)

y=( 2tu)1/3

y=1/3 (2t/u)^(-2/3) ( 2/u + 2td(1/u/dt)

now consider the last term
d(1/u)/dt=d 1/(t^2-4)=-2t/(t^2-4)^2

check my work

Answer 2

where did you get u from