Asked by lori
factory completely 21y^2+38+5
Answers
Answered by
Reiny
Did you mean
21y^2 + 38y + 5 ??
if so then
(3y+5)(7y+1) are the factors
21y^2 + 38y + 5 ??
if so then
(3y+5)(7y+1) are the factors
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