Asked by Anonymous
A machine in an ice factory exerts 3.06 ✕ 102 N of force to pull a large block of ice up a frictionless slope at constant speed. The force is applied parallel to the slope, and the weight of the block is 1.39 ✕ 104 N. What is the angle of the slope?
Answers
Answered by
Elena
mgsinα=F
sinα=F/mg=3.06x10^6/1.39x10^4 =0.022
α= 1,26 degr
sinα=F/mg=3.06x10^6/1.39x10^4 =0.022
α= 1,26 degr
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