Asked by jane

2 more problems -

Factory is to be bulit on a lot 180 x 240 . Local building code - specifies that lawn uniform width and equal in area of the factory which it surrounds. What must the width of this lawn be? Dimensions of the factory.

Answers

Answered by drwls
Let x be the required width. The factory area will be
(240-2x)(180-2x). That must equal half of (240x180), which is 21,600.
Solve the quadratic equation
(240-2x)(180-2x)= 21,600
It can be rewritten as
(120-x)(90-x) = 5400
or
x^2 - 210 x + 5400 = 0

(x-30)(x-180) = 0
There are two roots, but only one makes sense. A lawn 180 m wide would overlap and leave no room for the factory.
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