pH = 10
pH + pOH = pKw = 14
Solve for pOH, then
pOH = -log(OH^-).
KOH is a strong base; therefore, (OH^-) = (KOH).
What is the molarity of KOH in a solution that has pH of 10.0?
1 answer
1 answer
1 answer
1 answer
1 answer
1 answer