Question

1. (a) What is the molarity of a solution prepared by dissolving 4.315 g of NaOH in water to exactly 100 mL in a graduated flask? (Na = 23.0; O = 16.0' H = 1.0 amu).
   (b) What volume of the above solution is required to neutralize exactly 25.00 mL of 0.1500 M HCl solution?
    NaOH(aq)  +  HCl(aq) = NaCl(aq) + H2O(l)

Answer 1

mol NaOH = grams/molar mass= ?
M = mols/L = ? mols/0.1L

b)
mols HCl = M x L = ?
mols NaOH = mols HCl
M NaOH = mols/L soln. You know M NaOH and mols NaOH, solve for L NaOH and convert to mL if you wish.

Answer 2

Can you please plug in the numbers this is so confusing.