Asked by Cara
A centrifuge accelerates uniformly from rest to 18000 rpm in 180 s. Through how many revolutions did it turn in this time?
Answers
Answered by
bobpursley
d=wi*t+1/2 a t^2
revolutions= 0+1/2 (18000rpm/180)180^2
or you could have used
revolutions= avg veloicty*time
revolutions= 0+1/2 (18000rpm/180)180^2
or you could have used
revolutions= avg veloicty*time
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