The random variable X has a PDF of the form:
fX(x) = {1/x^2, for x >= 1,
0, otherwise.}
Let Y = X^2. For Y >= 1, the PDF of Y takes the form fY(y) = a/y^b. Find the values of a and b.
a =
b =
The random variable Q is uniform on [0, 1]. Conditioned on Q = q, the random variable X is Bernoulli with parameter q.
a) The conditional variance, Var(X | Q), is equal to:
b) Recall that a uniform random variable on [0, 1] has a variance of 1/12 and also satisfies E[Q^2] = 1/3. Then:
Var(E [X | Q]) =
E[Var(X | Q)] =
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