Asked by Morgan

The enthalpy formation of ethanol, C2H5OH, is -277.0 kJ/mol @ 298.15 K. Calculate the enthalpy of combustion of one mole of ethanol, assuming that the products are CO2(g) & H2O (l).
Answered by DrBob222
C2H5OH + 3O2 ==> 2CO2 + 3H2O
deltaHrxn = (2*DHfCO2)+(3*DHfH2O)-(DHfC2H5OH = ??
Answered by nathan
32.5
Answered by Anonymous
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