Asked by Bereket Tesefaye
The enthalpy of formation of caesium chloride is -44.28kjmol-1 and enthalpy of sublimation of caesium is +77.66kjmol-1.With other data from other sources calculate the lattice energy of CsCl(s)?
Answers
Answered by
DrBob222
1. Cs(s) ==> Cs(g) ..............dH = 77.66 kJ/mol
2. Cs(s) ==> Cs^+ + e...........dH = look up ionization
3. Cl2(g) ==> 2Cl(g)....................dH = look up Cl-Cl dissociation energy
4. Cl(g) + e ==> Cl^- ...............dH = look up electron affinity
Cs(s) + 1/2 Cl2 ==> CsCl ....dH formation = -44/28 kJ/mol
dHf = 1 + 2 + 3 + 4 + U where U = lattice energy. Solve for U.
I will post a URL that will show you how to do this with NaCl.
2. Cs(s) ==> Cs^+ + e...........dH = look up ionization
3. Cl2(g) ==> 2Cl(g)....................dH = look up Cl-Cl dissociation energy
4. Cl(g) + e ==> Cl^- ...............dH = look up electron affinity
Cs(s) + 1/2 Cl2 ==> CsCl ....dH formation = -44/28 kJ/mol
dHf = 1 + 2 + 3 + 4 + U where U = lattice energy. Solve for U.
I will post a URL that will show you how to do this with NaCl.
Answered by
DrBob222
//www.sarthaks.com/932021/calculate-the-lattice-energy-of-sodium-chloride-using-born-haber-cycle
Answered by
Fami kamal
Fami
Answered by
Hth
Yes
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