Please help me solve the following. Thanks,

Question

Write m^p = q using logarithms.

Solve (1/e)^2x = 14

Answer 1

by definition m^p = q is the same as

log_m q = p

for your second question

(1/e)^2x = 14

e^(-2x) = 14
-2x = ln 14
x = -1/2 ln 14

Are you not familiar with the basic properties of logs and exponents?
These type of questions require you to know those.