Asked by cam
A heater caused the temperature of a 550 g Aluminum block to change from 22 degrees C to 145 degrees C. How many calories were required to heat the metal block?
Answers
Answered by
DrBob222
q = mass x specific heat x (Trinal-Tinitial)
q = 550 x specific heat Al x (145-22)
Look up the specific heat Al in your text or notes and punch the calculator.
q = 550 x specific heat Al x (145-22)
Look up the specific heat Al in your text or notes and punch the calculator.
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