Asked by suzy
a 25v heater has two elements, one of which is missing. if the resistance of the remaining element is measured to be 50 ohm,what must the resistance of a second element be when connected in parallel to maintain a current of 1 amp.
Answers
Answered by
Damon
i = 25/Requivalent = 1 amp
so we need
Req = 25
In parallel
Req = R1R2/(R1+R2)
25 = 50 R2/(50+R2)
25 (50 + R2) = 50 R2
50 + R2 = 2 R2
R2 = 50
which we could have guessed :)
so we need
Req = 25
In parallel
Req = R1R2/(R1+R2)
25 = 50 R2/(50+R2)
25 (50 + R2) = 50 R2
50 + R2 = 2 R2
R2 = 50
which we could have guessed :)
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