Asked by jojo
An electrical heater is used to add 19.50 kJ of heat to a constant-volume calorimeter. The temperature of the calorimeter increases by 4.50°C. When 1.75 g of butanol (C4H9OH) is burned in the same calorimeter, the temperature increases by 14.58°C. Calculate the molar heat of combustion for butanol (enter in kJ).
Answers
Answered by
DrBob222
Ccal = 19,500 Joules/4.5 C = 4333.33 J/C.
For 1.75 butanol, moles
1.75 x (1 mol butanol/74.123) = ??
heat generated = 14.58 C x 4,333.33 J/C = 63,179.95 Joules and that divided by moles should give you the heat of combustion per mole. I get something like 2,676 kJ/mol.
For 1.75 butanol, moles
1.75 x (1 mol butanol/74.123) = ??
heat generated = 14.58 C x 4,333.33 J/C = 63,179.95 Joules and that divided by moles should give you the heat of combustion per mole. I get something like 2,676 kJ/mol.
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